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標題:

簡易方程式(5識做)

發問:

b+bc-2ac ab---------------- -- -----+5-(-6)+a c 1----- -(27-3x)=6 6 2(3x+7)------------ + 1 = 9 7 5(x+2) 3(3x+8)---------- = ------------- 9 18 b--- = 7 5 3c 15----- ... 顯示更多 b+bc-2ac ab ---------------- -- ----- +5-(-6)+a c 1 ----- -(27-3x)=6 6 2(3x+7) ------------ + 1 = 9 7 5(x+2) 3(3x+8) ---------- = ------------- 9 18 b --- = 7 5 3c 15 ----- = ----- 8 4 4y-12 --------- + 9 = 17 6 12y-25 ----------- - 4 = 9 13

最佳解答:

(b+bc-2ac)/[5-(-6)+a]-(ab)/c =[c(b+bc-2ac)]/ [c(b+bc-2ac)]- (11+a)(ab)/ [c(11+a)] =[c(b+bc-2ac)-(11+a)(ab)] /c(11+a) 1/6 -(27-3x)=6 1-162+18x = 36 18x-161=36 18x=197 x=197/8 2(3x+7)/7 + 1 = 9 2(3x+7)/7= 8 2(3x+7)=56 3x+7=28 3x=27 x=9 5(x+2)/9= 3(3x+8)/18 5(x+2) = 3(3x+8)/2 10(x+2) = 3(3x+8) 10x+20 =9x+24 x=4 b/5 = 7 b=35 3c/8 = 15/4 3c/2 = 15 3c=30 c=10 (4y-12)/6 + 9 = 17 (4y-12)/6=8 4y-12 = 48 4y=60 y= 15 (12y-25)/13 - 4 = 9 (12y-25)/13 = 13 12y-25=169 12y=194 y=194/12

其他解答:6A560DB68EC65D60