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F.5 MATHS
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F.5 MATHS................................... 圖片參考：http://imgcld.yimg.com/8/n/HA00002921/o/701011070069213873409640.jpg
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(a) Slope of L1=-2/3 =>Slope of L2=3/2 The equation of L2 is (y-2)=(3/2)(x-0) 2y-4=3x 3x-2y+4=0 (b) The intersection point of L1 and L2 is obtained by sloving 2x+3y-19=0 3x-2y+4=0 That is (2,5) The radius is sqrt[(2-0)^2+(5-2)^2]=sqrt(13) So C: (x-0)^2+(y-2)^2=13 or x^2+y^2-4y+4=13
其他解答:6A560DB68EC65D60
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