標題:
F.2 Maths (急)
發問:
Simplify the following expression. (a2b+ab2)/(3x2+3xy)÷(ab+a2)/(x2y)
最佳解答:
(a2b+ab2)/(3x2+3xy)÷(ab+a2)/(x2y) =(a2b+ab2)/(3x2+3xy)．(x2y)/(ab+a2) =[ab(a+b)]/[3x(x+y)]．(x2y)/[a(b+a)] =b/3(x+y)．xy =bxy/3(x+y) 2006-12-18 17:53:17 補充： Just group the common factors and canel them out.
其他解答:
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