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Maths question!SoS!

發問:

1.The length of rectancle ABCD is (2x-6)cm, the breadth is 1/2cm.Each side of square PQRS is 7cm.If rectancle ABCD and square PQRS have the same perimeter, find the value of x. 2. x-(x/4)-7=2 The answer is? (要列明步驟！) 更新: 2. x-(x/4)-7=2 The answer is? (要列明步驟！)

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1. ((2x-6)+1/2)*2=7*4 4x-12+1=28 4x=39 x=39/4 2. x-(x/4)-7=2 (x-(x/4)-7)*4=2*4 4x-x-28=8 3x=36 x=12 2007-10-08 20:41:59 補充： 第一題搞錯左[(2x-6)+(1/2x)]*2=7*42(2.5x-6)=28x=8

其他解答:

1.The length of rectangle ABCD is (2x-6) am, the breadth is 1/2x cm. Each side of square PQRS is 7 cam. If rectangle ABCD and square PQRS have the same perimeter, find the value of x. {The answer is 8.} [(2x-6)+(1/2x)]*2=7*4 2(2.5x-6)=28 x=8 2.x-(x/4)-7=2