標題:
問PHY 2004 CE MC Q.20 AND Q.25
發問:
問PHY 2004 CE MC Q.20 AND Q.25 可唔可以解釋下個答案點黎?
20. For I, the better insulated polystyrene container can reduce heat lost to the surrounding. So, less energy is supplied to raise the same liquid for the same temperature in latter situation. By E = mlv lv = E/m So, less energy is required and lv decreases. For II, this is another method to lower heat lost to the surrounding. So, lv decreases. 25. Since path difference = S1P - S2P = λ Constructive interference occurs when path difference = nλ, where n is a non-negative integer. So, constructive interference occurs at P. For 2, it is incorrect. It is because a trough can also be formed at P. For 3, If wavelength is doubled, then path difference = λ'/2 Destructive interference occurs when path difference = (n + 1/2)λ, where n is a non-negative interger. So, the answer is C
其他解答:
問PHY 2004 CE MC Q.20 AND Q.25
發問:
問PHY 2004 CE MC Q.20 AND Q.25 可唔可以解釋下個答案點黎?
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最佳解答:20. For I, the better insulated polystyrene container can reduce heat lost to the surrounding. So, less energy is supplied to raise the same liquid for the same temperature in latter situation. By E = mlv lv = E/m So, less energy is required and lv decreases. For II, this is another method to lower heat lost to the surrounding. So, lv decreases. 25. Since path difference = S1P - S2P = λ Constructive interference occurs when path difference = nλ, where n is a non-negative integer. So, constructive interference occurs at P. For 2, it is incorrect. It is because a trough can also be formed at P. For 3, If wavelength is doubled, then path difference = λ'/2 Destructive interference occurs when path difference = (n + 1/2)λ, where n is a non-negative interger. So, the answer is C
其他解答:
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