close
標題:
發問:
ce Maths 03 (q.34,41,42)
最佳解答:
34. There are 6 balls inthe bag in which 2 of them are green. P(at most 4 draws) = 1 – P(5 draws required) (atmost 4 draws and 5 draws are mutually exclusive) = 1 – (4 / 6)(3 / 5)(2 /4)(1 / 3) = 14 / 15 The answer is C. 41. This question is outof syllabus in CE mathematics, but it is in the syllabus of CE additionalmathematics. Sum of roots, α + β = 3 As α is one of the root, α2 - 3α + k =0 gives α2 = 3α – k α2 + 3β = 3α+ 3β – k = 3(α + β) – k = 3(3) – k = 9 – k The answer is C. 42. The graph shows y =-x2 + ax + b For the graph is openingdownward, i.e. the coefficient of x2 must be negative. Finding the y –intercept, it is negative. Put x = 0, i.e. y = b While y < 0, i.e. b< 0 The line of symmetry: x= -a / 2(-1) = a / 2, which is positive So, a > 0 The answer is C.
其他解答:
- 十分急, 有勞翻譯至中文!!!!謝謝!!!!!@1@
- PES2008 & FIFA 08
- 本人十分想懷孕,,請問在經期開始當天計算,最易受孕的日子會在那幾天-@1@
- 打籃球,要1號好定係11號好-@1@
- ( 22 點 ) 數碼暴龍 05 主角一問,,,@1@
- 十分急, 有勞翻譯至中文!!!!謝謝!!!!!@1@
- PES2008 & FIFA 08
- 本人十分想懷孕,,請問在經期開始當天計算,最易受孕的日子會在那幾天-@1@
- 打籃球,要1號好定係11號好-@1@
- ( 22 點 ) 數碼暴龍 05 主角一問,,,@1@
此文章來自奇摩知識+如有不便請留言告知
ce MATHS MC 急!!!發問:
ce Maths 03 (q.34,41,42)
最佳解答:
34. There are 6 balls inthe bag in which 2 of them are green. P(at most 4 draws) = 1 – P(5 draws required) (atmost 4 draws and 5 draws are mutually exclusive) = 1 – (4 / 6)(3 / 5)(2 /4)(1 / 3) = 14 / 15 The answer is C. 41. This question is outof syllabus in CE mathematics, but it is in the syllabus of CE additionalmathematics. Sum of roots, α + β = 3 As α is one of the root, α2 - 3α + k =0 gives α2 = 3α – k α2 + 3β = 3α+ 3β – k = 3(α + β) – k = 3(3) – k = 9 – k The answer is C. 42. The graph shows y =-x2 + ax + b For the graph is openingdownward, i.e. the coefficient of x2 must be negative. Finding the y –intercept, it is negative. Put x = 0, i.e. y = b While y < 0, i.e. b< 0 The line of symmetry: x= -a / 2(-1) = a / 2, which is positive So, a > 0 The answer is C.
其他解答:
文章標籤
全站熱搜
留言列表
